Find the division of the following by synthetic division method: $p(t) = 2t^2 + 3t + 1$ by $t + 2$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) To divide $p(t) = 2t^2 + 3t + 1$ by $t + 2$ using synthetic division:
$1$. Identify the root of the divisor $t + 2 = 0$,which is $t = -2$.
$2$. Write the coefficients of the dividend $p(t) = 2t^2 + 3t + 1$,which are $2, 3, 1$.
$3$. Perform synthetic division:
- Bring down the first coefficient: $2$.
- Multiply by the root: $2 \times (-2) = -4$.
- Add to the next coefficient: $3 + (-4) = -1$.
- Multiply by the root: $(-1) \times (-2) = 2$.
- Add to the next coefficient: $1 + 2 = 3$.
$4$. The resulting coefficients are $2$ and $-1$,representing the quotient $2t - 1$.
$5$. The final value $3$ is the remainder.
Quotient polynomial: $2t - 1$;
Remainder polynomial: $3$.

Explore More

Similar Questions

If the zero of the polynomial $p(x) = 3x^{3} - x^{2} - ax - 45$ is $3$,then $a = \dots$

Verify that $3$ is a zero of the linear polynomial $p(x) = 4x - 12$.

The product of the zeros of the polynomial $x^{3}+4x^{2}+x-6$ is .............

State the degree of the given polynomial: $p(x) = 5x^{100} - (x^{10})^{20} + 3(x^2)^{25} + 2x^{25} - 7$

The value of $p(x) = 4x^3 + 3x^2 + 2x + 1$ at $x = 1$ is $\ldots \ldots \ldots$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo